# how to measure home ac current 110v / 200v with arduino

The cool thing about an ACS712 is that current is measured is measured in two directions. What this means is that if we sample fast enough and long enough, we sure to find the peak in one direction and the peak in another direction.

With both peaks known, it is a matter of knowing the shape of the waveform to calculate the current. In the case of line or mains power, we know that waveform to be a SINE wave. Knowing that allows us to apply a basic electronic formula to yield a decent result.

This tutorial will show you how this is done.

# Getting an ACS712

They are readily available at any of the following vendors:

# Discussion of the Basic Methology Applied

## Finding the RMS Value

In most cases, an expression of AC current will be in a value known as RMS. In order to use the ACS712 current sensor to measure AC current, it is important to understand how to calculate an RMS current value from the device readings.

The formula that is applied here is very basic and is right out of any basic electricity or electronics manual.

With an ACS712, current measurements are reported with a voltage output. In this tutorial, we will calculate the RMS volts and apply the ACS712 scale factor.

Conversion for a sine wave with a zero volt offset (like your mains or line power) is performed as follows…

**1)** Find the peak to peak voltage ( Volts Peak to Peak )

**2)** Divide the peak to peak voltage by two to get peak voltage (Volts Peak)

**3)** Multiply the peak voltage by 0.707 to yield rms volts (Volts RMS)

Having Calculated RMS voltage, is simply a matter of multiplying by the scale factor of the particular ACS712 to yield the RMS value of the current being measured.

## Arduino Sampling for the Peaks

The values out of the ACS712 are constantly changing when measuring AC Current. In order ensure that you have come very close to finding the peaks, you need to sample fast enough and long enough. Because mains or line power is at a frequency of 50 to 60 hz, the Arduino will be fast enough provided it takes consecutive samples with little or no interruption.

In this tutorial, there is a function dedicated to doing just that.

# Arduino ACS712 Current Measurement Tutorial

NOTE:This works for lower voltage measurements and perhaps experimentally at a higher line voltage. This should not be used in a permanent line voltage application.

## Arduino ACS712 AC Measurement Tutorial Setup

Fundamental to performing this tutorial safely is knowing what the current rating of your ACS712 and the amount of current that your load requires.

Connect the components as shown below:

## The ACS712 Arduino AC Current Tutorial Sketch

Copy, Paste and Upload the code below. Also take a look at how I make a call to the ‘getVPP‘ function from the main loop. In that function, I take interupted AC samples for one second while recording the maximum and minimum values. From this I will calculate the peak to peak voltage measured. I’ve found this to be extremely effective for line power frequencies.

Mind you, my power is pretty clean. If you’ve got a lot of spikes, getting a meaningful measurement could be tough.

/* Measuring AC Current Using ACS712 */ const int sensorIn = A0; int mVperAmp = 185; // use 100 for 20A Module and 66 for 30A Module double Voltage = 0; double VRMS = 0; double AmpsRMS = 0; void setup(){Serial.begin(9600); } void loop(){ Voltage = getVPP(); VRMS = (Voltage/2.0) *0.707; AmpsRMS = (VRMS * 1000)/mVperAmp;Serial.print(AmpsRMS);Serial.println(" Amps RMS"); } float getVPP() { float result; int readValue; //value read from the sensor int maxValue = 0; // store max value here int minValue = 1024; // store min value here uint32_t start_time = millis(); while((millis()-start_time) < 1000) //sample for 1 Sec { readValue = analogRead(sensorIn); // see if you have a new maxValue if (readValue > maxValue) { /*record the maximum sensor value*/ maxValue = readValue; } if (readValue < minValue) { /*record the maximum sensor value*/ minValue = readValue; } } // Subtract min from max result = ((maxValue - minValue) * 5.0)/1024.0; return result; }

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